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point_load.jpg face_load.jpg

Hello everybody,

Pic.1 shows a point load (1N) on a node.
Pic.2 shows a face load on a square face (5mm*2).
The point load is in the middle of the section of the face load.
How can i convert the point load to a equivalent force load (???)with marc2005r2?
What's the relation between a point load and a face load?

Many thanks in advance!
hhpp

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Well,
as you already have found out yourself:

"The conversion from 1 N point load to the face load on a 5 mm*2 area is as follows: pressure = 1N/5mm*2 = 0.2 N/mm*2"

Correct.

Martin

p.s.
I hope you are using consistent units in your model. The coordinates of the nodes must be given in mm and Young's modulus in N/mm*2. Then you should get similar results in both cases.

[Diese Nachricht wurde von Martin Stumvoll am 19. Okt. 2005 editiert.]

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Thank you, Martin.

The current point load can insure a moment of 8Nmm on the fixed line, only under the condition that the point load is in the middle of the section of the face load. The face load as you said is equivalent to the point load. That means that the moment on the fixed line is also 8Nmm. In brief, the formula you mentioned is correct only when the point load is applied to the middle of the section.

My question is how to calculate the face load if the point load is not in the medial position.
hhpp

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You need the center of graphity of the face. The distance to the fixed line (projected) is the "length".
And then simply:  Moment = pressure x area x length

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Thank you very much!

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